Help me understand why Datatables doesn't work...

Help me understand why Datatables doesn't work...

djduffer26djduffer26 Posts: 2Questions: 1Answers: 0
edited October 2023 in Free community support

Hi guys, my name is Giuseppe and I'm writing to you from Italy. I recently discovered Datatables and I'm studying it a bit. I would like your help to understand why Datatables isn't working in my code. What mistakes am I making? I will copy my code and attach a photo of the index.php page. Thank you in advance.

//mi connetto al database
$mysqli = mysqli_connect("localhost", "root", "", "interventi");

if (mysqli_connect_errno()) {
  echo "Errore nella connessione al database: " . mysqli_connect_error();

//eseguo la query nella tabella "CLIENTI"
$query = "SELECT * FROM clienti";

$result = mysqli_query($mysqli, $query);

//Creare una pagina HTML con una tabella che contiene le intestazioni delle colonne della tabella del database.
<!DOCTYPE html>
<html lang="en">
    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <link rel="stylesheet" href="" />
    <script src=""></script>
    <script src=""></script>

    <div id="container">
        <div id="header">
            <div id="navigation">

        <div id="container2">

<table id="clienti">
    <th>DATA INTERVENTO</th>
    <th>TIPO CONTRATTO</th>
//Usare un ciclo while per scorrere le righe del risultato e stampare i valori delle colonne nella tabella HTML.
//Puoi usare la funzione mysqli_fetch_assoc per ottenere un array associativo con i nomi delle colonne come chiavi e i valori come valori.
//Puoi usare i tag <tr> e <td> di HTML per creare le righe e le celle della tabella.
while ($row = mysqli_fetch_assoc($result)) {
    $denominazione = $row["denominazione"];
    $indirizzo = $row["indirizzo"];
    $localita = $row["localita"];
    $email = $row["email"];
    $operatore = $row["operatore"];
    $intervento = $row["intervento"];
    $data_intervento = $row["data_intervento"];
    $tipo_contratto = $row["tipo_contratto"];
    echo "<tr>";
    echo "<td>$denominazione</td>";
    echo "<td>$indirizzo</td>";
    echo "<td>$localita</td>";
    echo "<td>$email</td>";
    echo "<td>$operatore</td>";
    echo "<td>$intervento</td>";
    echo "<td>$data_intervento</td>";
    echo "<td>$tipo_contratto</td>";
    echo "</tr>";
<?php mysqli_close($mysqli); ?>
$(document).ready( function () {
} );

Edited by Kevin: Syntax highlighting. Details on how to highlight code using markdown can be found in this guide


  • kthorngrenkthorngren Posts: 19,891Questions: 26Answers: 4,691

    Start by looking at your browser's console for errors. You will probably see something like this:

    Uncaught ReferenceError: jQuery is not defined

    The load order of the Javascript files is important. Datatables requires jQuery so it needs to be loaded first. Change the order of lines 8 and 9 to this:

        <script src=""></script>
        <script src=""></script>

    I think Datatables will add this but you should put your table rows in a tbody. See the HTML requirements for more info.


  • djduffer26djduffer26 Posts: 2Questions: 1Answers: 0

    wauuu A thousand thanks!!! it worked great!

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